Solar Payback Calculator
How many years until your solar system has paid for itself? Cost, production, own use and tariffs.
Estimate how much electricity your solar panels produce, from the system size and the sun at your location.
Enter the size of the system in kWp, the average peak sun hours per day at your location and the performance ratio. You get the production per day, month and year, and what it is worth. It is an estimate for planning, not a yield guarantee.
Enter your values to see the result.
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A 5 kWp system with 3 peak sun hours and an 80 % performance ratio makes 5 × 3 × 0.8 = 12 kWh a day, about 4,380 kWh a year.
Real production varies with the weather from year to year, with roof angle and direction, shading and panel ageing. For a precise yield of your roof use a tool such as PVGIS or ask your installer for a simulation.
kWp (kilowatt-peak) is the rated power of the panels, measured under standard test conditions: 1,000 W of sunlight per m² at a cell temperature of 25 °C. kWh is energy: how much electricity the system actually delivers over a day or a year.
So there is no fixed factor that turns kWp into kWh. You need two things from your site: how much sun reaches the panels, and how much is lost on the way to the socket. Together they give the yield per kWp, and kWh per year = kWp × kWh per kWp.
With peak sun hours, as in this calculator: kWh per day = kWp × peak sun hours × performance ratio.
With the yearly solar irradiation on the panels, the form used in engineering standards such as IEC 61724: kWh per year = irradiation on the panels (kWh/m² per year) × kWp × performance ratio. Both give the same result, because the yearly irradiation divided by 365 equals the daily peak sun hours.
Example for Germany: Fraunhofer ISE gives about 1,270 kWh/m² a year on south-facing panels tilted 20 to 25°, which is about 3.5 peak sun hours a day. A 5 kWp system with a performance ratio of 85 % then makes about 1,270 × 5 × 0.85 ≈ 5,400 kWh a year, or about 1,080 kWh per kWp.
Production per year for common system sizes. Pick the column that matches the yield per kWp at your location.
| System size | 800 kWh/kWp | 1,000 kWh/kWp | 1,200 kWh/kWp | 1,600 kWh/kWp |
|---|---|---|---|---|
| 1 kWp | 800 kWh | 1,000 kWh | 1,200 kWh | 1,600 kWh |
| 3 kWp | 2,400 kWh | 3,000 kWh | 3,600 kWh | 4,800 kWh |
| 5 kWp | 4,000 kWh | 5,000 kWh | 6,000 kWh | 8,000 kWh |
| 8 kWp | 6,400 kWh | 8,000 kWh | 9,600 kWh | 12,800 kWh |
| 10 kWp | 8,000 kWh | 10,000 kWh | 12,000 kWh | 16,000 kWh |
| 15 kWp | 12,000 kWh | 15,000 kWh | 18,000 kWh | 24,000 kWh |
Typical yields: about 800 kWh/kWp in the UK (median load factor of feed-in tariff installations 2024/25: 9.2 %), about 1,080 kWh/kWp for a new south-facing system in Germany, and up to about 1,600 kWh/kWp in southern Spain or North Africa (Fraunhofer ISE). Older, shaded or poorly oriented systems make less.
Sources: UK Government: Feed-in Tariff load factor analysis 2024/25 · Fraunhofer ISE: Recent facts about photovoltaics in Germany · European Commission JRC: PVGIS solar irradiation and yield tool
Turn the formula round: kWp = kWh per year ÷ yield per kWp. To produce 4,000 kWh a year where 1,000 kWh per kWp is realistic, you need about 4 kWp, for example 10 panels of 400 Wp.
Producing as much as you use over a year does not mean you use all of it yourself, because most solar power comes at midday and in summer. The Solar Payback Calculator shows what the split between own use and feed-in means for the money.
Written and reviewed by QLines, Cologne · Last reviewed
Multiply the system size by the yield per kWp at your location: kWh per year = kWp × kWh per kWp. Per day it is kWp × peak sun hours × performance ratio. There is no fixed factor, because the sun differs from place to place.
About 800 kWh in the UK, about 1,000 to 1,100 kWh for a new south-facing system in Germany, and up to about 1,600 kWh in very sunny regions such as southern Spain.
About 8,000 kWh a year in the UK, around 10,000 to 11,000 kWh on a good south-facing roof in Germany, and up to about 16,000 kWh in very sunny regions.
Not quite. kWp is the DC power the panels deliver under standard test conditions. The AC power the inverter feeds into the house is usually a little lower, and on most days the panels stay below their peak rating.
It depends on the system size and the sun at your location: kWh per day = kWp × peak sun hours × performance ratio. A 5 kWp system with 3 peak sun hours and 80 % ratio makes about 12 kWh a day.
The number of hours per day with the full 1 kW/m² of sunshine that would give the same energy as the real day. It equals the daily solar irradiation in kWh per m². Look up your location in PVGIS.
kWp (kilowatt-peak) is the output of the panels under standard test conditions. It is the usual way to state the size of a solar system.
The share of the ideal output that is left after losses in the inverter, cables, temperature and shading. A good system often has about 75 to 85 %.
How many years until your solar system has paid for itself? Cost, production, own use and tariffs.
What does a device cost to run? Watts, hours and your price give the kWh and the cost per day, month and year.
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